0=3q^2-7q+2

Solution for 0=3q^2-7q+2 equation:

0=3q^2-7q+2

We move all terms to the left:

0-(3q^2-7q+2)=0

We add all the numbers together, and all the variables

-(3q^2-7q+2)=0

We get rid of parentheses

-3q^2+7q-2=0

a = -3; b = 7; c = -2;
Δ = b2-4ac
Δ = 72-4·(-3)·(-2)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-5}{2*-3}=\frac{-12}{-6}
=+2
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+5}{2*-3}=\frac{-2}{-6}
=1/3
$